Integrand size = 11, antiderivative size = 47 \[ \int x^m (a+b x)^n \, dx=\frac {x^{1+m} (a+b x)^n \left (1+\frac {b x}{a}\right )^{-n} \operatorname {Hypergeometric2F1}\left (1+m,-n,2+m,-\frac {b x}{a}\right )}{1+m} \]
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Time = 0.01 (sec) , antiderivative size = 47, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {68, 66} \[ \int x^m (a+b x)^n \, dx=\frac {x^{m+1} (a+b x)^n \left (\frac {b x}{a}+1\right )^{-n} \operatorname {Hypergeometric2F1}\left (m+1,-n,m+2,-\frac {b x}{a}\right )}{m+1} \]
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Rule 66
Rule 68
Rubi steps \begin{align*} \text {integral}& = \left ((a+b x)^n \left (1+\frac {b x}{a}\right )^{-n}\right ) \int x^m \left (1+\frac {b x}{a}\right )^n \, dx \\ & = \frac {x^{1+m} (a+b x)^n \left (1+\frac {b x}{a}\right )^{-n} \, _2F_1\left (1+m,-n;2+m;-\frac {b x}{a}\right )}{1+m} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 47, normalized size of antiderivative = 1.00 \[ \int x^m (a+b x)^n \, dx=\frac {x^{1+m} (a+b x)^n \left (1+\frac {b x}{a}\right )^{-n} \operatorname {Hypergeometric2F1}\left (1+m,-n,2+m,-\frac {b x}{a}\right )}{1+m} \]
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\[\int x^{m} \left (b x +a \right )^{n}d x\]
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\[ \int x^m (a+b x)^n \, dx=\int { {\left (b x + a\right )}^{n} x^{m} \,d x } \]
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Result contains complex when optimal does not.
Time = 2.79 (sec) , antiderivative size = 34, normalized size of antiderivative = 0.72 \[ \int x^m (a+b x)^n \, dx=\frac {a^{n} x^{m + 1} \Gamma \left (m + 1\right ) {{}_{2}F_{1}\left (\begin {matrix} - n, m + 1 \\ m + 2 \end {matrix}\middle | {\frac {b x e^{i \pi }}{a}} \right )}}{\Gamma \left (m + 2\right )} \]
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\[ \int x^m (a+b x)^n \, dx=\int { {\left (b x + a\right )}^{n} x^{m} \,d x } \]
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\[ \int x^m (a+b x)^n \, dx=\int { {\left (b x + a\right )}^{n} x^{m} \,d x } \]
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Timed out. \[ \int x^m (a+b x)^n \, dx=\int x^m\,{\left (a+b\,x\right )}^n \,d x \]
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